- Reference
Definition
- Namespace:
- System
- Assembly:
- System.Runtime.dll
- Assembly:
- mscorlib.dll
- Assembly:
- netstandard.dll
Important
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Returns a new string in which a specified number of characters from the current string are deleted.
Overloads
| Remove(Int32) | Returns a new string in which all the characters in the current instance, beginning at a specified position and continuing through the last position, have been deleted. |
| Remove(Int32, Int32) | Returns a new string in which a specified number of characters in the current instance beginning at a specified position have been deleted. |
Remove(Int32)
Returns a new string in which all the characters in the current instance, beginning at a specified position and continuing through the last position, have been deleted.
public: System::String ^ Remove(int startIndex);public string Remove (int startIndex);member this.Remove : int -> stringPublic Function Remove (startIndex As Integer) As StringParameters
- startIndex
- Int32
The zero-based position to begin deleting characters.
Returns
String
A new string that is equivalent to this string except for the removed characters.
Exceptions
ArgumentOutOfRangeException
startIndex is less than zero.
-or-
startIndex specifies a position that is not within this string.
Examples
The following example demonstrates the Remove method. The next-to-last case removes all text starting from the specified index through the end of the string. The last case removes three characters starting from the specified index.
// This example demonstrates the String.Remove() method.using namespace System;int main(){ String^ s = "abc---def"; // Console::WriteLine( "Index: 012345678" ); Console::WriteLine( "1) {0}", s ); Console::WriteLine( "2) {0}", s->Remove( 3 ) ); Console::WriteLine( "3) {0}", s->Remove( 3, 3 ) );}/*This example produces the following results:Index: 0123456781) abc---def2) abc3) abcdef*/// This example demonstrates the String.Remove() method.using System;class Sample{ public static void Main() { string s = "abc---def"; Console.WriteLine("Index: 012345678"); Console.WriteLine("1) {0}", s); Console.WriteLine("2) {0}", s.Remove(3)); Console.WriteLine("3) {0}", s.Remove(3, 3)); }}/*This example produces the following results:Index: 0123456781) abc---def2) abc3) abcdef*/// This example demonstrates the String.Remove() method.let s = "abc---def"printfn "Index: 012345678"printfn $"1) {s}"printfn $"2) {s.Remove 3}"printfn $"3) {s.Remove(3, 3)}"(*This example produces the following results:Index: 0123456781) abc---def2) abc3) abcdef*)' This example demonstrates the String.Remove() method.Class Sample Public Shared Sub Main() Dim s As String = "abc---def" ' Console.WriteLine("Index: 012345678") Console.WriteLine("1) {0}", s) Console.WriteLine("2) {0}", s.Remove(3)) Console.WriteLine("3) {0}", s.Remove(3, 3)) End SubEnd Class''This example produces the following results:''Index: 012345678'1) abc---def'2) abc'3) abcdef'Remarks
In the .NET Framework, strings are zero-based. The value of the startIndex parameter can range from zero to one less than the length of the string instance.
Note
This method does not modify the value of the current instance. Instead, it returns a new string in which all characters from position startIndex to the end of the original string have been removed.
See also
- Int32
- Concat(Object)
- Insert(Int32, String)
- Join(String, String[])
- Replace(Char, Char)
- Split(Char[])
- Substring(Int32)
- Trim(Char[])
Applies to
Remove(Int32, Int32)
Returns a new string in which a specified number of characters in the current instance beginning at a specified position have been deleted.
public: System::String ^ Remove(int startIndex, int count);public string Remove (int startIndex, int count);member this.Remove : int * int -> stringPublic Function Remove (startIndex As Integer, count As Integer) As StringParameters
- startIndex
- Int32
The zero-based position to begin deleting characters.
- count
- Int32
The number of characters to delete.
Returns
String
A new string that is equivalent to this instance except for the removed characters.
Exceptions
ArgumentOutOfRangeException
Either startIndex or count is less than zero.
-or-
startIndex plus count specify a position outside this instance.
Examples
The following example demonstrates how you can remove the middle name from a complete name.
using namespace System;int main(){ String^ name = "Michelle Violet Banks"; Console::WriteLine( "The entire name is '{0}'", name ); // remove the middle name, identified by finding the spaces in the middle of the name->->. int foundS1 = name->IndexOf( " " ); int foundS2 = name->IndexOf( " ", foundS1 + 1 ); if ( foundS1 != foundS2 && foundS1 >= 0 ) { name = name->Remove( foundS1 + 1, foundS2 - foundS1 ); Console::WriteLine( "After removing the middle name, we are left with '{0}'", name ); }}// The example displays the following output:// The entire name is 'Michelle Violet Banks'// After removing the middle name, we are left with 'Michelle Banks'using System;public class RemoveTest{ public static void Main() { string name = "Michelle Violet Banks"; Console.WriteLine("The entire name is '{0}'", name); // Remove the middle name, identified by finding the spaces in the name. int foundS1 = name.IndexOf(" "); int foundS2 = name.IndexOf(" ", foundS1 + 1); if (foundS1 != foundS2 && foundS1 >= 0) { name = name.Remove(foundS1 + 1, foundS2 - foundS1); Console.WriteLine("After removing the middle name, we are left with '{0}'", name); } }}// The example displays the following output:// The entire name is 'Michelle Violet Banks'// After removing the middle name, we are left with 'Michelle Banks'let name = "Michelle Violet Banks"printfn $"The entire name is '{name}'"// Remove the middle name, identified by finding the spaces in the name.let foundS1 = name.IndexOf " "let foundS2 = name.IndexOf(" ", foundS1 + 1)if foundS1 <> foundS2 && foundS1 >= 0 then let name = name.Remove(foundS1 + 1, foundS2 - foundS1) printfn $"After removing the middle name, we are left with '{name}'"// The example displays the following output:// The entire name is 'Michelle Violet Banks'// After removing the middle name, we are left with 'Michelle Banks'Public Class RemoveTest Public Shared Sub Main() Dim name As String = "Michelle Violet Banks" Console.WriteLine("The entire name is '{0}'", name) Dim foundS1 As Integer = name.IndexOf(" ") Dim foundS2 As Integer = name.IndexOf(" ", foundS1 + 1) If foundS1 <> foundS2 And foundS1 >= 0 Then ' remove the middle name, identified by finding the spaces in the middle of the name... name = name.Remove(foundS1 + 1, foundS2 - foundS1) Console.WriteLine("After removing the middle name, we are left with '{0}'", name) End If End SubEnd Class ' The example displays the following output:' The entire name is 'Michelle Violet Banks'' After removing the middle name, we are left with 'Michelle Banks'Remarks
In the .NET Framework, strings are zero-based. The value of the startIndex parameter can range from zero to one less than the length of the string instance.
Note
This method does not modify the value of the current instance. Instead, it returns a new string in which the number of characters specified by the count parameter have been removed. The characters are removed at the position specified by startIndex.
See also
- Int32
- Concat(Object)
- Insert(Int32, String)
- Join(String, String[])
- Replace(Char, Char)
- Split(Char[])
- Substring(Int32)
- Trim(Char[])
